![]() |
|
Suppose we are given two
partitions
and
and we need to
calculate
.
The computation of
:

So, ![]()
Now we will compute
:

There are no more new blocks
either in
or
in
such that
, so
When we carry out the same operations with other elements, we can get:

So, ![]()
Now it is obvious that:

Also;
Last update: 28 July, 2004